(1/2x-1)^2+(1/2x-1)-72=0

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Solution for (1/2x-1)^2+(1/2x-1)-72=0 equation:


x in (-oo:+oo)

((1/2)*x-1)^2+(1/2)*x-72-1 = 0

(1/2*x-1)^2+x/2-72-1 = 0

(2*(1/2*x-1)^2)/2+x/2+(-72*2)/2+(-1*2)/2 = 0

2*(1/2*x-1)^2+x-72*2-1*2 = 0

1/2*x^2-x-144-2+2 = 0

1/2*x^2-x-142-2 = 0

1/2*x^2-x-144 = 0

1/2*x^2-x-144 = 0

1/2*x^2-x-144 = 0

DELTA = (-1)^2-(-144*1/2*4)

DELTA = 289

DELTA > 0

x = (289^(1/2)+1)/(1/2*2) or x = (1-289^(1/2))/(1/2*2)

x = 18 or x = -16

(x+16)*(x-18) = 0

((x+16)*(x-18))/2 = 0

((x+16)*(x-18))/2 = 0 // * 2

(x+16)*(x-18) = 0

( x+16 )

x+16 = 0 // - 16

x = -16

( x-18 )

x-18 = 0 // + 18

x = 18

x in { -16, 18 }

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